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iStudentNurse
iStudentNurse • 1 year ago

Cystic Fibrosis Punnett Square: Parents that are heterozygous for the gene, or are both carriers but do not express the disease, have a 25% that their child will be a genotype for CF & express the disease, 50% that the child will be a carrier (genotype but will not express CF), and a 25% chance that the child will not have the disease, nor be a carrier

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